Welcome Anonymous; Register or Login for more.
home Home  > Forums  > General > Acropolis
World news and the arts

Re: Official HomeWork Help Thread

Postby nza » Fri Sep 18, 2009 4:30 am

Those are called disjoint sets.
Flareon is the PS3 of Pokémon: it ain't got shit. ~ Top
Image
User avatar
nza
Brock Level
 
Posts: 7279
Joined: Wed Aug 15, 2007 2:00 am
Location: TX 4 LYF
Platinum FC: 1634 0051 3444
White FC: 3825 8255 2193

i need help! seriously!

Postby Keyman » Thu Jan 14, 2010 1:41 pm

im doing a world history 2 project based on the inventions made in the early times of the US, and I was chosen to do the bike.....


The problem is that there's a question that asks how does the bike solve problems?


well other than being a faster way of transportation, does anyone else have any ideas?
Image

"Im just doing my duty, don't take it personal!"- Chun Li
User avatar
Keyman
 
Posts: 3514
Joined: Fri Oct 02, 2009 2:13 pm
Location: whoa! why do you need to know?
HeartGold FC: 0732 9211 9467
3DS FC: 0860 3366 9731

Re: i need help! seriously!

Postby RDS1 » Thu Jan 14, 2010 4:19 pm

Doesn't it have, like, the most efficient force input/output ratio of any form of transportation, or something?

I don't know; I'm working from the memory of something I heard one time about three and a half years ago (I think; I wasn't paying close attention).

You should probably try asking in the Homework Help topic, or whatever it's called.
Image
User avatar
RDS1
 
Posts: 43659
Joined: Wed Aug 15, 2007 8:03 pm

Re: i need help! seriously!

Postby superflous » Thu Jan 14, 2010 11:01 pm

Yeah, don't ask the lounge, nobody ever comes here.

Also, convenience, can go anywhere pretty much, eco-friendly, etc.
Image
User avatar
superflous
 
Posts: 43516
Joined: Wed Aug 15, 2007 10:30 pm

Re: i need help! seriously!

Postby RDS1 » Fri Jan 15, 2010 12:19 am

Exercise?
Image
User avatar
RDS1
 
Posts: 43659
Joined: Wed Aug 15, 2007 8:03 pm

Re: i need help! seriously!

Postby Ze Colonel » Fri Jan 15, 2010 1:15 am

Eco-friendly.
Cheap (in comparisons to other options).
Still in use today, when there are faster methods.
It exercises your body, while getting you somewhere faster than walking.
Perfect for going places a car cannot. A ride in the park, a bike up a mountain trail.
Can be used in sports and tricks for entertainment or as a profession.

And I'm sure others~

Moved. Too lazy to keep up the "hudur not mod" since it gets somewhat obvious. We still have one more anon anyways.
Code: Select all
Top Hat says
the hair is too well groomed
i say this as a rin expert

http://pastebin.com/FtUZjRyM http://i.imgur.com/yU1Jw.png
User avatar
Ze Colonel
Brock Level
 
Posts: 10024
Joined: Wed Aug 15, 2007 10:29 pm
Location: Pretty places.
Platinum FC: 1634-2226-2194
SSBB FC: 0645-5458-4397
HeartGold FC: 3094-9280-0631
White FC: 2837-9485-5030
3DS FC: 0516-7274-0788

Re: Official HomeWork Help Thread

Postby nza » Fri Jan 15, 2010 3:35 am

Easier to manage than a horse.
- no horseshit
- no feeding
- no tieing up a live animal to a post
- no saddle maintenance
- reduced cost of care for horse (no more food, additional housing, etc); aka economically its more viable
- user friendly
Flareon is the PS3 of Pokémon: it ain't got shit. ~ Top
Image
User avatar
nza
Brock Level
 
Posts: 7279
Joined: Wed Aug 15, 2007 2:00 am
Location: TX 4 LYF
Platinum FC: 1634 0051 3444
White FC: 3825 8255 2193

Re: Official HomeWork Help Thread

Postby MikkelDemey » Thu Jan 28, 2010 10:58 am

It's the fastest on short distances through a city.
.md
User avatar
MikkelDemey
 
Posts: 7378
Joined: Wed Aug 15, 2007 8:27 am
Location: Belgium
Diamond FC: 0731 4301 1101

Re: Official HomeWork Help Thread

Postby Thunder_man6 » Mon Feb 08, 2010 12:46 am

I know this is /really/ easy I just for some reason can't think today and I can't get the right answer.

Simplify the expression. Write the answer using only positive exponents.

(((a^3)(b^6)(a^-1)(b^5))/(a^5)(b^3)))^-2



Edit: I'll see if this way of looking at it is less confusing:

( a^3 * b^6 * a^-1 * b^5
-------------------------- -2
a^5 * b^3)
</feeling dumb>
Image
I'm sick of always hearing
All the
sad songs on the radio
All day it is there to remind
An over sensitive guy
That he's
lost and alone
User avatar
Thunder_man6
Dex Contributor
 
Posts: 4284
Joined: Wed Aug 15, 2007 10:42 pm
Location: Stevens Point, Wisconsin
Diamond FC: 1418-3931-7653
Pearl FC: 3910-1066-6005
Platinum FC: 2535-9501-5165
SSBB FC: 1461-5884-4238
SoulSilver FC: 4770-1088-4477

Re: Official HomeWork Help Thread

Postby superflous » Mon Feb 08, 2010 2:00 am

Er, so...

a3b6a-1b5
a5b3

All to the -2?

I'm not writing carrots >_>

Well, first off, I'd bring a^-1 down, because negative exponents= pretty much flip that part.
So, a^-1= 1/a

So, that would then be
a3b6b5
a5b3a

When you multiply the same variable, you add the exponents.
Which is why a*a= a^2 because a^1*a^1== a^1+1

So, simplify

a3b11
a6b3

Now, it is the reverse when you divide, meaning you subtract exponents, so...

a^3-6 b^11-3
Which is
b^8
a^3

And then, when you have something like this (a^2)^2 you multiply the exponents.

SO

b^-16
a^-6

Flip!

a^6
b^16

Therefore...

a^6/b^16

QED!!!!!!!!!!!!!!!
cOOKIES
Image
User avatar
superflous
 
Posts: 43516
Joined: Wed Aug 15, 2007 10:30 pm

Re: Official HomeWork Help Thread

Postby Chaos Oblivion » Fri Feb 19, 2010 1:53 am

If anyone is good at chemistry, then I present you a challenge:

1. A gold sphere with a mass of 1,200. kg and a temperature of 100.0°C was plunged into
an insulated vat of water. The mass of the water was 2.000 kg and its initial temperature
was 25.00°C.
a. What will be the final temperature of the system when stabilized?
b. Determine the radius of the sphere (in inches).

I'd appreciate an explanation on how to reach the answer as well.
Image
User avatar
Chaos Oblivion
 
Posts: 1601
Joined: Thu Aug 16, 2007 2:08 am
Location: Brooklyn, NY
Diamond FC: 1847 9019 4732
Pearl FC: 1031 9582 8255

Re: Official HomeWork Help Thread

Postby Thunder_man6 » Fri Feb 26, 2010 3:58 am

For the life of me I can't figure this out, I must be having an off night as this should be really easy.


Factor the polynomial by factoring out the opposite of the GCF.
-15(x^10)(y^3)+27(x^9)(y^2)-18(x^8)(y^2)
Image
I'm sick of always hearing
All the
sad songs on the radio
All day it is there to remind
An over sensitive guy
That he's
lost and alone
User avatar
Thunder_man6
Dex Contributor
 
Posts: 4284
Joined: Wed Aug 15, 2007 10:42 pm
Location: Stevens Point, Wisconsin
Diamond FC: 1418-3931-7653
Pearl FC: 3910-1066-6005
Platinum FC: 2535-9501-5165
SSBB FC: 1461-5884-4238
SoulSilver FC: 4770-1088-4477

Re: Official HomeWork Help Thread

Postby Hype » Sun Mar 28, 2010 3:56 pm

You've been out of school too long when a homework help thread looks like gibberish :(
>:O >:I >:O >:I
User avatar
Hype
 
Posts: 4707
Joined: Wed Aug 15, 2007 11:28 am

Re: Official HomeWork Help Thread

Postby MikkelDemey » Sun Mar 28, 2010 10:42 pm

Hype wrote:You've been out of school too long when a homework help thread looks like gibberish :(

It's them young kids with their hip language and their loud musics. Always playing on my lawn.

http://www.theblazingcenter.com/wp-cont ... -cane1.jpg

Stay the hell off it.
.md
User avatar
MikkelDemey
 
Posts: 7378
Joined: Wed Aug 15, 2007 8:27 am
Location: Belgium
Diamond FC: 0731 4301 1101

Re: Official HomeWork Help Thread

Postby Clanjos » Tue Jun 22, 2010 10:40 pm

Find the point P on the graph of
y=1/(2 x)
such that the line through P and (1, 1/2) has slope -4/5.
IMPORTANT: Provide exact expressions, not decimal approximations.

Find all values of k such that the equation
x^2+kx+17=0
has one solution. If there is only one answer, enter it in both answer boxes. If there are two solutions, enter the SMALLER solution in the first answer box and the LARGER solution in the second answer box.


Copied directly. Your aid, if you please.
Image
Image

Chunx wrote:Way to spoiled the game. Now I cant get an orgasm when I unlock them.


~Chunx
User avatar
Clanjos
 
Posts: 1215
Joined: Thu Aug 16, 2007 10:06 pm
Pearl FC: 5283-8045-8852

Quick Reply

   
PreviousNext

Return to Acropolis

Who is online

Users browsing this forum: No registered users and 1 guest